Write the domain of the function $y = sec^{-1}x$

The correct answer is $\mathbb{R}−(−1,1)$

Here, $f(x)=y=sec^{−1}x$

So, $x=sec$ $y$


The range of $sec$ $y$ is the domain of $sec^{−1}x$


$sec$ $y$ is possible in $\mathbb{R}$ −(−1,1)

So the Range of secy is $\mathbb{R}$−(−1,1)


∴ The domain of $f(x)=sec^{−1}x$ is $\mathbb{R}−(−1,1)$ = $(−∞,−1] U [1,∞)$